MIDB Function

Зміст

# MIDB

Returns a text string of a DBCS text. The parameters specify the starting position and the number of characters.

Ця фукція доступна з версії LibreOffice 4.2.

#### Syntax

MIDB("Text"; Start; Number_bytes)

Text is the text containing the characters to extract.

Start is the position of the first character in the text to extract.

Number_bytes specifies the number of characters MIDB will return from text, in bytes.

#### Example

=MIDB("中国";1;0) returns "" (0 bytes is always an empty string).

=MIDB("中国";1;1) returns " " (1 byte is only half a DBCS character and therefore the result is a space character).

=MIDB("中国";1;2) returns "中" (2 bytes constitute one complete DBCS character).

=MIDB("中国";1;3) returns "中 " (3 bytes constitute one and a half DBCS character; the last byte results in a space character).

=MIDB("中国";1;4) returns "中国" (4 bytes constitute two complete DBCS characters).

=MIDB("中国";2;1) returns " " (byte position 2 is not at the beginning of a character in a DBCS string; 1 space character is returned).

=MIDB("中国";2;2) returns " " (byte position 2 points to the last half of the first character in the DBCS string; the 2 bytes asked for therefore constitutes the last half of the first character and the first half of the second character in the string; 2 space characters are therefore returned).

=MIDB("中国";2;3) returns " 国" (byte position 2 is not at the beginning of a character in a DBCS string; a space character is returned for byte position 2).

=MIDB("中国";3;1) returns " " (byte position 3 is at the beginning of a character in a DBCS string, but 1 byte is only half a DBCS character and a space character is therefore returned instead).

=MIDB("中国";3;2) returns "国" (byte position 3 is at the beginning of a character in a DBCS string, and 2 bytes constitute one DBCS character).

=MIDB("office";2;3) returns "ffi" (byte position 2 is at the beginning of a character in a non-DBCS string, and 3 bytes of a non-DBCS string constitute 3 characters).